There need to be squares in there for x and y - I think you're asking for the centre of the circle with equation:
(x + 5)2 + (y - 3)2 = 56
in which case the centre is (-5, 3)
A circle with centre (xo, yo) and radius r has equation of the form:
(x - xo)2 + (y - yo)2 = r2
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
(-7,5)
(-4,3)
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
(-7,5)
(-4,3)
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
(-4, 3)
(8,-8)
(-5, 3)
(x-9)2 + y2 = 484The center is atx = 9y = 0The radius of the circle is 22 .
(-4,-6)