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a. (2,6). you draw it on a graph (x,y) b. c. d. make the triangle, a. lies between b. and c.
b
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What is the area of a triangle with base of 4'' and a height of 10''?
The area of a triangle is (1/2) x (length of the base) x (height of the triangle). You ought to be able to handle it from this point.
Which point lies outside the circle with equation (x - 2)2 (y 3)2 4?
2,0
What is the area of a triangle 4 in by 2 in?
The area of triangle is : 4.0
If a triangle has an area of 16 and a base of 4 what is the height of the triangle?
area of triangle =(1/2)(base)(height) 16=(1/2)(4)h h=8
The length of three sides of the triangle are 4 feet 6 feet and 9 feet Is the triangle a right triangle?
A triangle with sides measuring ; 4 feet , 6 feet and 9 feet is a right triangle. A triangle is a right triangle as long as it has one 90 degree point.
What is the of a triangle that has a base of 12'' and a height of 4''?
Area of triangle = 1/2 base times height1/2 * 12 * 4 = 24
What is the purpose of an orthocenter?
In short, the orthocenter really has no purpose. There are 4 points of Concurrency in Triangles: 1) The Centroid - the point of concurrency where the 3 medians of a triangle meet. This point is also the triangle's center of gravity. 2) The Circumcenter - the point of concurrency where the perpendicular bisectors of all three sides of the triangle meet. This point is the center of the triangle's circumscribed circle. 3) The Incenter - the point of concurrency where the angle bisectors of all three angles of the triangle meet. Like the circumcenter, the incenter is the center of the inscribed circle of a triangle. 4) The Orthocenter - the point of concurrency where the 3 altitudes of a triangle meet. Unlike the other three points of concurrency, the orthocenter is only there to show that altitudes are concurrent. Thus, bringing me back to the initial statement.
An isosceles right triangle has a hyptenuse of 4 What is the area of the triangle?
if hypotenuse is 4 then each side is 4 divided by sqrt 2 = 2.828 with two angles 45 degrees The triangle height is 2 so area is 1/2 base x height =1/2 times 4 times 2 = 4
What Are The 4 Types Of Congruent Triangles?
1. Isoceles triangle 2. saclane triangle 3.equlateral triangle
The three sides of a triangle is 2 and 3 and 4 what is the area of the triangle?
3 units2
What is area of triangle base of 6 and height of 4?
If it is a right triangle its 6*4/2=12squared if not the its simply 6*4=24sqaured
What is the area of an equilateral triangle inscribed in a circle of radius 4cm?
Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.
