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If we're talking Width, Length and Perimeter then W = P/2 - L
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Can you solve the equation 6 equals -10-p over 5?
If the equation is 6 = -10 - p/5 then multiply all terms by 5 :-30 = -50 - p : p = -50 - 30 = -80
Which equation could be used to find l the length of each piece of pipe in inches if a pipe 100 inches long is to be divided into p pieces?
l = 100/p inches.
How do you determine length and width if given the area and perimeter?
If length = L and width = W then area A = L*W and perimeter P = 2(L+W). So, from the area equation, L = A/W Substituting this in the equation for P gives P=2(A/W + W) = 2A/W + 2W Then multiplying through by W gives PW = 2A + 2W2 or, in standrad form, 2W2 - PW + 2A = 0 Then W = 1/4*[P +/- sqrt(P2 - 16A)] The two solutions of this quadratic will be W and L.
What is solution to L plus U - M plus P?
There can be no solution because there is no equation (or inequality) but only an expression.
What rule do you see about the relationship between the length and width of a rectangle and its perimeter?
The perimeter is equal to the length of each side added together, and a rectangle has four sides, so the equation could be written as s1+s2+s3+s4=P. However, because opposite sides of a rectangle are equal in length, we can call s1 and s2 "L" and s3 and s4 "W" and rewrite the equation as L+L+W+W=P, which simplifies to 2L+2W=p, or finally 2(L+W)=P.
What is the answer to this inequality 3p - 6 21?
The answer to the equation is p is equal to nine. You solve the equation by putting like terms together and then solving for p.
Is P equals l times V an expression or formula?
its a equation
Can you solve the equation 6 equals -10-p over 5?
If the equation is 6 = -10 - p/5 then multiply all terms by 5 :-30 = -50 - p : p = -50 - 30 = -80
How do you write an equation when the perimeter and width are known but the length is needed?
P = perimeter, W = width, L = length P = 2(W + L) = 2W + 2L 2L = P - 2W L = P/2 - W
What is L plus L plus C equals P?
A little more info would be nice but as it stands your equation is 2L + C = P
The perimeter of a rectangular field is P feet The width of the field is 200 feet less than its length In terms of P what is the length of the field in Feet?
P = 2 x (L + W), so L + W = 100 ie P/2 = L + W W = L - 200 so P/2 = L + L - 200 = 2L - 200 therefore L = P/4 + 100
Which equation could be used to find l the length of each piece of pipe in inches if a pipe 100 inches long is to be divided into p pieces?
l = 100/p inches.
How do you determine length and width if given the area and perimeter?
If length = L and width = W then area A = L*W and perimeter P = 2(L+W). So, from the area equation, L = A/W Substituting this in the equation for P gives P=2(A/W + W) = 2A/W + 2W Then multiplying through by W gives PW = 2A + 2W2 or, in standrad form, 2W2 - PW + 2A = 0 Then W = 1/4*[P +/- sqrt(P2 - 16A)] The two solutions of this quadratic will be W and L.
The length of rectangle is 5 less than twice the width The perimeter of the rectangle is 80. Find the dimensions of the rectangle?
L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15 L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15
What is solution to L plus U - M plus P?
There can be no solution because there is no equation (or inequality) but only an expression.
What rule do you see about the relationship between the length and width of a rectangle and its perimeter?
The perimeter is equal to the length of each side added together, and a rectangle has four sides, so the equation could be written as s1+s2+s3+s4=P. However, because opposite sides of a rectangle are equal in length, we can call s1 and s2 "L" and s3 and s4 "W" and rewrite the equation as L+L+W+W=P, which simplifies to 2L+2W=p, or finally 2(L+W)=P.
How do you find the length if you have the perimeter and the width?
Equation for perimeter of a rectangle: p = 2l + 2w or: p = 2(l+w) Solve any of the previous equations for the length.
