P = 2 x (L + W), so L + W = 100 ie P/2 = L + W
W = L - 200 so P/2 = L + L - 200 = 2L - 200 therefore L = P/4 + 100
in math terms, the perimeter is the measure around the shape.
Perimeter is a unit of length. Area is a unit of area. The two units are not directly convertible.However, the area of a rectangle is length times width, and the perimeter is two times length plus two times width. Given constant perimeter, a square has maximum area, while a very thin rectangle has nearly zero area. (In calculus terms, the limit of the area as length or width goes to zero is zero.)Depending on how you want to name your units, you can always find a rectangle whose perimeter is "larger" than area, but this is a numerical trick that is not valid in any school of thought of mathematics that I know.
It is not possible to give a straightforward answer to this question because the person who posted the question forgot to describe the square!If the length of each side of the square is s cm, then its perimeter is 4*s cm. In terms of metres, that is 4*s/100 = s/25 metres.
It isn't possible to give a generalised formula for the circumference of an ellipse in terms of elementary functions. The circumference (or perimeter) of an oval is represented by an infinite series based on multiple aspects of the oval including: * Eccentricity * Implied length ("major radius") * Implied width ("minor radius")
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
If you add the length and width together, it will always be half of the perimeter. In terms of an equation, it would look like so: Perimeter = (2 x Length) + (2 x Width)
A perimeter is a length. It cannot be expressed in terms of area.
A rectangular prism. If every edge is the same length, then it is a cube.
The formula for the perimeter of a rectangle is: p = 2(l + w) In other words, just add all four sides. You can't calculate the perimeter of the rectangle if you know only the length.
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x2 + 13x
x2+13x
The length of the rectangular slab = LThe width of the rectangular slab = WThe formula for perimeter in terms of the length and width is 2L + 2W = 60The area =L*W = 224So L=224/WWe substitute that into the formula for perimeter and we haveP=2(224/w)+2w=60This can be simplified tow2-30w+224=0 so we can solve it and find w.Fortunately, it factors or else we would need to use the quadratic equation.(w-14)(w-16)=0. Now we use the zero product rule and we findthe solutions are 14 and 16. This means the rectangle is 14x16. We need to check the answer.We note that 14x16=224 so that is the desired area and 14x2+16x2=28+32=60 which is the desired perimeter.
breadth = 4x - 10 ie length + breadth = 5x - 10. Perimeter is double this figure ie 10x - 20 or 10(x - 2)
If we're talking Width, Length and Perimeter then W = P/2 - L
in math terms, the perimeter is the measure around the shape.
Here is what you are supposed to do: * Convert to consistent units. For example, convert the cm to mm. * Write an equation for the diagonal (in terms of length and width). Replace the known diagonal. * Write an equation for the area, in terms of length and width. * Solve the two equations simultaneously. * Calculate the perimeter.