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P = 2 x (L + W), so L + W = 100 ie P/2 = L + W

W = L - 200 so P/2 = L + L - 200 = 2L - 200 therefore L = P/4 + 100

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Q: The perimeter of a rectangular field is P feet The width of the field is 200 feet less than its length In terms of P what is the length of the field in Feet?
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What are perimeter?

in math terms, the perimeter is the measure around the shape.


Rectangle whose perimeter is larger than area?

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What is the perimeter or circumference of an oval or ellipse?

It isn't possible to give a generalised formula for the circumference of an ellipse in terms of elementary functions. The circumference (or perimeter) of an oval is represented by an infinite series based on multiple aspects of the oval including: * Eccentricity * Implied length ("major radius") * Implied width ("minor radius")


What is the length and width of a rectangle that has a perimeter of 20 inches and an area of 24.4524 square inches showing work with final answers?

What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in

Related questions

How does the length and width of a rectangle relate to the perimeter?

If you add the length and width together, it will always be half of the perimeter. In terms of an equation, it would look like so: Perimeter = (2 x Length) + (2 x Width)


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The length of a rectangular backyard is 13 feet longer than its width (x) What is the area of the backyard in terms of x?

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What is the length and width of a rectangle with the perimeter of 60 and an area of 224?

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