An hexagon has 6 sides and a pentagon has 5 sides
If the hexagon has side length s, then the apothem is sqrt(3) * s / 2.
There is no simple answer. For an equilateral triangle it is 6.9282/s where s is the length of each side. For a square it is 4/s A regular pentagon: 2.9062/s A regular hexagon: 2.3094/s and so on. The ratio for a circle is 2/r where r is the radius. For irregular polygons there is no rule.
The perimeter is 5 times the side length. A = 5s
A pentagon has 5 sides.A regular pentagon has every side the same length.Perimeter = 5 x 3s= 15 s(whatever unit a s is, other than a second.)
P = 5s, where s is the length of a side. This applies to a regular pentagon. If the pentagon is irregular then P = (s1 + s2 + s3 + s4 + s5)
A hexagon is divided into 6 equilateral triangles; the circle around the hexagon has a radius the length of one of these triangles. So the circumference is S x 2pi, s being the side of the hexagon. The perimeter of the hexagon is 6s. So the relationship is that you multiply it by 1/3 pi
Perimeter would be 5 times s (5*s).
H, I, O, S, X, Z. l as for the shapes circle, square, rectangle, equilateral triangle, any regular polygon (pentagon, hexagon...)
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
measure 1 (S) side of the hexagon, write it down, measure across from corner to another in a straight line, divide it in half (R) multiply S by R and multiply by 3, youll have your answer
9 centimetres,as 54/6 is 9
No.