There is no simple answer.
For an equilateral triangle it is 6.9282/s where s is the length of each side.
For a square it is 4/s
A regular pentagon: 2.9062/s
A regular hexagon: 2.3094/s and so on.
The ratio for a circle is 2/r where r is the radius.
For irregular polygons there is no rule.
The areas of two similar decagons are in the ratio of 625 ft² to 100 ft², which simplifies to 6.25:1. Since the ratio of the perimeters of similar shapes is the square root of the ratio of their areas, we take the square root of 6.25, which is 2.5. Therefore, the ratio of the perimeters of the decagons is 2.5:1.
The sacle factor between two shapes is the same as the ratio of their perimeters.
They are the same.
Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.
If two polygons are similar, then the ratio of their perimeters is the same as the ratio of their corresponding sides. Therefore, the correct answer is C. the same as. This means that if the ratio of the lengths of corresponding sides is ( k ), then the ratio of their perimeters is also ( k ).
The ratio of their perimeters will be 3:1, while the ratio of their areas will be 9:1 (i.e. 32:1)
The areas of two similar decagons are in the ratio of 625 ft² to 100 ft², which simplifies to 6.25:1. Since the ratio of the perimeters of similar shapes is the square root of the ratio of their areas, we take the square root of 6.25, which is 2.5. Therefore, the ratio of the perimeters of the decagons is 2.5:1.
The ratio of their perimeters is also 45/35 = 9/7. The ratio of their areas is (9/7)2 = 81/63
The ratio is 16 to 81.
Whatever the ratio of perimeters of the similar figures, the areas will be in the ratios squared. Examples: * if the figures have perimeters in a ratio of 1:2, their areas will have a ratio of 1²:2² = 1:4. * If the figures have perimeters in a ratio of 2:3, their areas will have a ratio of 2²:3² = 4:9.
It is 0.6046 : 1 (approx).
is it 3:5 and 3:5
Their perimeters are in the same ratio.
The sacle factor between two shapes is the same as the ratio of their perimeters.
They are the same.
Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.
If lengths are in the ratio a:b, then areas are in the ratio a2:b2 since area is length x length. If areas are in the ratio c:d, then lengths are in the ration sqrt(c):sqrt(d). Areas of decagons are 625sq ft and 100 sq ft, they are in the ratio of 625:100 = 25:4 (dividing through by 25 as ratios are usually given in the smallest terms). Thus their lengths are in the ratio of sqrt(25):sqrt(4) = 5:2 As perimeter is a length, the perimeters are in the ratio of 5:2.