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There is no simple answer.
For an equilateral triangle it is 6.9282/s where s is the length of each side.
For a square it is 4/s
A regular pentagon: 2.9062/s
A regular hexagon: 2.3094/s and so on.
The ratio for a circle is 2/r where r is the radius.
For irregular polygons there is no rule.
What else can I help you with?
If the areas of two similar decagons are 625 ft2 and 100 ft2 what is the ratio of the perimeters of the decagons?
The areas of two similar decagons are in the ratio of 625 ft² to 100 ft², which simplifies to 6.25:1. Since the ratio of the perimeters of similar shapes is the square root of the ratio of their areas, we take the square root of 6.25, which is 2.5. Therefore, the ratio of the perimeters of the decagons is 2.5:1.
How do scale factor and ratio of perimeters compare?
The sacle factor between two shapes is the same as the ratio of their perimeters.
Ratio of perimeters given ratio of similitude?
They are the same.
What are two different size squares that the ratio of their perimeters is the same as the ratio of their areas?
Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.
If two polygons are similar then the ratio of their perimeters is the ratio of their corresponding sides. A. the square of B. the sum of C. the same as D. greater than?
If two polygons are similar, then the ratio of their perimeters is the same as the ratio of their corresponding sides. Therefore, the correct answer is C. the same as. This means that if the ratio of the lengths of corresponding sides is ( k ), then the ratio of their perimeters is also ( k ).
Two triangles are similar and have a ratio of similarity of 3 1 What is the ratio of their perimeters and the ratio of their areas?
The ratio of their perimeters will be 3:1, while the ratio of their areas will be 9:1 (i.e. 32:1)
If the areas of two similar decagons are 625 ft2 and 100 ft2 what is the ratio of the perimeters of the decagons?
The areas of two similar decagons are in the ratio of 625 ft² to 100 ft², which simplifies to 6.25:1. Since the ratio of the perimeters of similar shapes is the square root of the ratio of their areas, we take the square root of 6.25, which is 2.5. Therefore, the ratio of the perimeters of the decagons is 2.5:1.
What is the width of two similar rectangles are 45 yd and 35 yd what is the ratio of the perimeters of the areas?
The ratio of their perimeters is also 45/35 = 9/7. The ratio of their areas is (9/7)2 = 81/63
If the perimeters of two squares are in a ratio of 4 to 9 what is the areas of the two squares?
The ratio is 16 to 81.
What is the relationship between perimeters and areas of similar figures?
Whatever the ratio of perimeters of the similar figures, the areas will be in the ratios squared. Examples: * if the figures have perimeters in a ratio of 1:2, their areas will have a ratio of 1²:2² = 1:4. * If the figures have perimeters in a ratio of 2:3, their areas will have a ratio of 2²:3² = 4:9.
What is the ratio of the areas of an equilateral triangle and a circle if their perimeters are same?
It is 0.6046 : 1 (approx).
What is the similarity ratio and the ratio of the perimeters of two regular octagons with areas of 18in2 and 50in2?
is it 3:5 and 3:5
If the ratio of the side lengths of two similar polygons is 31 what is the ratio of the perimeters?
Their perimeters are in the same ratio.
How do scale factor and ratio of perimeters compare?
The sacle factor between two shapes is the same as the ratio of their perimeters.
Ratio of perimeters given ratio of similitude?
They are the same.
What are two different size squares that the ratio of their perimeters is the same as the ratio of their areas?
Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.
If the areas of two similar decagons are 625 sq ft and 100 sq ft what is the ratio of the perimeters of the decagons?
If lengths are in the ratio a:b, then areas are in the ratio a2:b2 since area is length x length. If areas are in the ratio c:d, then lengths are in the ration sqrt(c):sqrt(d). Areas of decagons are 625sq ft and 100 sq ft, they are in the ratio of 625:100 = 25:4 (dividing through by 25 as ratios are usually given in the smallest terms). Thus their lengths are in the ratio of sqrt(25):sqrt(4) = 5:2 As perimeter is a length, the perimeters are in the ratio of 5:2.
