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Find the area of a regular hexagon with a base of 10 and an apothem of 12?
14
What is the apothem of a regular hexagon with a radius of 8?
3 times the square root of 3
What is the area of a regular hexagon with apothem length of 24 inches?
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
What is the area of a regular hexagon if each sides is 11m the apothem is 9m and the radius is 10m?
297 M
What is the area of a regular hexagon with a side length of 2 centimeter and an apothem length of 10.4 centimeters?
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
Find the area of a regular hexagon with a base of 10 and an apothem of 12?
14
What is the perimeter of a hexagon with an apothem of 12?
The perimeter of a hexagon with an apothem of 12 is 83.14
What is the apothem of a inscribed regular hexagon with a radius of 20 inches?
The apothem of a regular hexagon can be calculated using the formula ( a = r \cdot \cos(\frac{\pi}{6}) ), where ( r ) is the radius. For a hexagon inscribed in a circle with a radius of 20 inches, the apothem becomes ( a = 20 \cdot \cos(30^\circ) = 20 \cdot \frac{\sqrt{3}}{2} = 10\sqrt{3} ) inches. Therefore, the apothem of the hexagon is approximately 17.32 inches.
What is the apothem of a regular hexagon with a radius of 8?
3 times the square root of 3
What is the apothem of a regular hexagon with a radius of 12 centimeters Round to the nearest tenth?
10.4 cm
What is the area of a regular hexagon with apothem length of 24 inches?
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
What is the Area of a regular hexagon with a base of 10 and an apothem of 20?
12 x 5 x 20 ie 1200squnits. I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?
What is the area of a regular hexagon with a side of 4 and an apothem of 3 46?
Easy. Since the side is the base and the apothem is the height of the triangle, multiply them and divide by two to get the area of the triangle. 3 * 3.46 = 10.38 /2 = 5.19. Then multiply by 6 to get the area of the hexagon. 5.19 * 6 = 31.14. You multiply by 6 because you can fit 6 regular triangles in a regular hexagon. We've already found the area of one regular triangle in the hexagon.
What is the area of a regular hexagon if each sides is 11m the apothem is 9m and the radius is 10m?
297 M
A regular hexagon has an apothem length of 14 m. What is the area of the hexagon Round to the nearest whole number?
It is 679 square metres.
A cake pan is in the shape of a regular hexagon with center E. Points A and C are midpoints of the sides. What is the apothem?
3.55
What is formula for finding area of hexagon?
Assuming that you are talking about a regular hexagon, the equation is (1/2)ap, a being the apothem and pbeing the perimeter. You can also use that equation for any other regular polygon.
