12 and its multiples.
Yes.
So pretty much it is the same rule as 4 and 6 because both # go into 24. 4 rule: look at the last to places to see if the # is divisible by 4. 6 rule: if the #is both divisible by 2 and 3 then it s divisible by 6.
If a number is divisible by both three and four, it's divisible by twelve.
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
numbers between 10 and 20 is divisible by both 4 and 6 = 12 & 18
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
4- If the last two digits are divisible by 4, the whole number is divisible by 4. 6- If the number is even and also divisible by 3, it is divisible by 6.
Any number that is divisible by both 2 and 3 is divisible by 6.
Something divisible by 6 has to be divisible by both 2 and 3. and that just answers that anything disible by 6 is divisible by 2
4 to 5 (since they are both divisible by 6)
4/6 can be reduced to 2/3, because both four and six are divisible by two.