This is easy using the point-slope formula of a line:
y - y1 = m(x - x1)
So, knowing that the slope m = 3, and x1 = -1, and y1 = 5, just plug these values into the equation above, then solve for y to get the equation in standard slope-intercept form.
If your point is positive positive it is in 1. If tour point is negative positive it is in 2. If your point it negative negative it is in 3. And if your point it positive negative it is in 4.
The coordinates must be as follows: First quadrant: positive, positive Second quadrant: negative, positive Third quadrant: negative, negative Fourth quadrant: positive, negative
The equation is [ y = 3 ].
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
If your point is positive positive it is in 1. If tour point is negative positive it is in 2. If your point it negative negative it is in 3. And if your point it positive negative it is in 4.
positive
No. If they were then there would be no point in having a negative.
It is negative
No! If they were the same what would be the point in calling them positive or negative?
The coordinates must be as follows: First quadrant: positive, positive Second quadrant: negative, positive Third quadrant: negative, negative Fourth quadrant: positive, negative
The equation is [ y = 3 ].
Choose the equation of the line that contains the points (1, -1) and (2, -2).
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
This is called the 'standard form' for the equation of a parabola:y =a (x-h)2+vDepending on whether the constant a is positive or negative, the parabola will open up or down.
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).