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This is easy using the point-slope formula of a line:

y - y1 = m(x - x1)

So, knowing that the slope m = 3, and x1 = -1, and y1 = 5, just plug these values into the equation above, then solve for y to get the equation in standard slope-intercept form.

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Q: Which is the equation of the line with the slope 3 that contains point negative 1 and positive 5?
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