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That depends on the equation.

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Q: Which pairs are solutions to the equation?
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Which of these ordered pairs are solutions to the equation 5x 1?

None of them.None of them.None of them.None of them.


A quadratic equation can't have one imaginary solution?

That's true. Complex and pure-imaginary solutions come in 'conjugate' pairs.


How do you find 3 different ordered pairs that are solutions of the equation?

Select any three values of x in the domain of the equation. Solve the equation at these three points for the other variable, y. Then each (x, y) will be an ordered pair that is a solution of the equation.


Which 2 order pairs are solutions of y x 5?

Which 2 order pairs are solutions of y x + 5


How can you determine whether a polynomial equation has imaginary solutions?

To determine whether a polynomial equation has imaginary solutions, you must first identify what type of equation it is. If it is a quadratic equation, you can use the quadratic formula to solve for the solutions. If the equation is a cubic or higher order polynomial, you can use the Rational Root Theorem to determine if there are any imaginary solutions. The Rational Root Theorem states that if a polynomial equation has rational solutions, they must be a factor of the constant term divided by a factor of the leading coefficient. If there are no rational solutions, then the equation has imaginary solutions. To use the Rational Root Theorem, first list out all the possible rational solutions. Then, plug each possible rational solution into the equation and see if it is a solution. If there are any solutions, then the equation has imaginary solutions. If not, then there are no imaginary solutions.

Related questions

A graph of the set of ordered pairs that are solutions of the equation?

Graph of an equation.


Which of these ordered pairs are solutions to the equation 5x 1?

None of them.None of them.None of them.None of them.


A quadratic equation can't have one imaginary solution?

That's true. Complex and pure-imaginary solutions come in 'conjugate' pairs.


How do you find 3 different ordered pairs that are solutions of the equation?

Select any three values of x in the domain of the equation. Solve the equation at these three points for the other variable, y. Then each (x, y) will be an ordered pair that is a solution of the equation.


If an equation is an identity how many solutions does it have?

An identity equation has infinite solutions.


Find three different ordered pairs that are solutions of the equation y equals 2x-1?

3


If an equation has a degree of three how many solutions will there be?

If the highest degree of an equation is 3, then the equation must have 3 solutions. Solutions can be: 1) 3 real solutions 2) one real and two imaginary solutions.


Which 2 order pairs are solutions of y x 5?

Which 2 order pairs are solutions of y x + 5


If the discriminant of a quadratic equation is -4 how many solutions does the equation have?

If the discriminant of a quadratic equation is less then 0 then it will have no real solutions.


How many solutions do a equation have?

It will depend on the equation.


How can you determine whether a polynomial equation has imaginary solutions?

To determine whether a polynomial equation has imaginary solutions, you must first identify what type of equation it is. If it is a quadratic equation, you can use the quadratic formula to solve for the solutions. If the equation is a cubic or higher order polynomial, you can use the Rational Root Theorem to determine if there are any imaginary solutions. The Rational Root Theorem states that if a polynomial equation has rational solutions, they must be a factor of the constant term divided by a factor of the leading coefficient. If there are no rational solutions, then the equation has imaginary solutions. To use the Rational Root Theorem, first list out all the possible rational solutions. Then, plug each possible rational solution into the equation and see if it is a solution. If there are any solutions, then the equation has imaginary solutions. If not, then there are no imaginary solutions.


How are the graph of an equation and the set of all solutions of an equation related?

The coordinates of every point on the graph, and no other points, are solutions of the equation.