The radial velocity ie velocity towards or away from your starting point.
It is NOT the ordinary speed or velocity because you can run in a circle around your starting point at top speed but the distance will not change so the slope of the distance time graph will be zero.
the physical quantity is distance and unit is meters
no, work done is the area under a force-distance graph
Unit of Measure
bar graph
Since distance is 1/2 at^2 where a is acceleration, it represents one half of the acceleration
the physical quantity is distance and unit is meters
If you mean 'measured by the area under the speed/time graph' then this is total distance travelled.
The distance covered in the direction of motion or the opposite direction. Distance covered in the transverse direction is not included.
It represent the distance covered is 40 metre.
Acceleration.
no, work done is the area under a force-distance graph
Distance travelled from a velocity / time graph can be calculated from area under graph, say area under (v/t) graph from 0 - 1 seconds = distance travelled after 1 second, then do 0 - 2 seconds, 0 - 3 etc for set of data for distance / time graph
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
Unit of Measure
bar graph
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
Since distance is 1/2 at^2 where a is acceleration, it represents one half of the acceleration