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2X - 5Y = 15

- 5Y = - 2X + 15

Y = (2/5)X - 3

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Y intercept = - 3

===============zero out Y to find X intercept

(2/5)X - 3 = 0

(2/5)X = 3

X = 15/2

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X intercept = 15/2

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Q: Which points form the x-and y-intercept of the equation 2x-5y15?

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The equations are equivalent.

The equation for the given points is y = x+4 in slope intercept form

Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2

Points: (4, 5) and (-3, -1) Slope: 6/7 Equation: 7y = 6x+11

Points: (9, 1) and (4, 16) Slope: -3 Equation: y = -3x+28

Related questions

You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)

The equations are equivalent.

The equation for the given points is y = x+4 in slope intercept form

We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.

Slope-intercept form

Points: (4, 1) and (5, 2) Slope: 1 Equation: y = x-3 Equation in its general form: x-y-3 = 0

Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2

Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14

Points: (4, 5) and (-3, -1) Slope: 6/7 Equation: 7y = 6x+11

Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: y = -1/14x-19/28 in slope intercept form

Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11

Points: (9, 1) and (4, 16) Slope: -3 Equation: y = -3x+28