Points: (-1, 2) and (5, 2)
Slope: 0
Equation: y = 2
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If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The equation for the given points is y = x+4 in slope intercept form
It is y = 2.
In general, a linear equation CANNOT be made to go through three points. That will only happen if the three points are collinear and in that case, the equation of the line will only require two points.
Answer this question…y = 2x + 6
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The equation for the given points is y = x+4 in slope intercept form
Y= -3x + 8
It is y = 2.
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
It is: y = 2 which is straight horizontal line with no slope that connects (-1, 2) to (5,2)
In general, a linear equation CANNOT be made to go through three points. That will only happen if the three points are collinear and in that case, the equation of the line will only require two points.
Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Answer this question…y = 2x + 6