Slope-intercept form
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
x2-x1/y2-y1 (-3 - 3)/(-3 - (-3)) (-6)/(0) The equation will be y = -6x + 0
Well, honey, if you're looking for a function that passes through the points (2, 15) and (3, 26), you're talking about a linear function. The slope of this function would be 11 (rise of 11 over run of 1), so the equation would be y = 11x + b. To find the y-intercept, plug in one of the points, let's say (2, 15), and solve for b. So, the function that passes through those points is y = 11x + 4.
The equation in slope-intercept form would be y=-2x
If a line has an undefined slope, it is vertical. The equation of a vertical line passing through the point (13) is written as ( x = 13 ). This indicates that for all points on the line, the x-coordinate remains constant at 13, while the y-coordinate can take any value.
who would know that answer
If a line is vertical, that means that all x values are the same, regardless of the y value. So if it passes through a point with an x value of -4, all points must have an x value of -4.So the equation would be x=-4.
yes there is it would be 10!!
It's not possible because the given points would be a vertical line parallel to the y axis
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
If -14 is the y intercept then it is: y = -1/13x -14
Points: (-3, -23) and (5, 9) Slope: 4 Equation: y = 4x-11