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If the equation of a line passes through the points (1, 3) and (0, 0), which form would be used to write the equation of the line?
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How would you find the equation of a line that passes through the points 3 -3 and -3 -3?
x2-x1/y2-y1 (-3 - 3)/(-3 - (-3)) (-6)/(0) The equation will be y = -6x + 0
Which function passes through the points (2 15) and (3 26)?
Well, honey, if you're looking for a function that passes through the points (2, 15) and (3, 26), you're talking about a linear function. The slope of this function would be 11 (rise of 11 over run of 1), so the equation would be y = 11x + b. To find the y-intercept, plug in one of the points, let's say (2, 15), and solve for b. So, the function that passes through those points is y = 11x + 4.
Which equation represents the line that passes through 0 0 and is parallel to the line passing through 2 3 and 6 1?
The equation in slope-intercept form would be y=-2x
A line segment has endpoints of Y(2,-3) and Z(-6,-1).a. Calculate the length of the line segment.b. Calculate the midpoint of the line segment.c. Determine the equation of the line that passes through the points Y and Z?
who would know that answer
What is the equation of a vertical line passing through open paranthesis negative 4 negative 3 close paranthesis?
If a line is vertical, that means that all x values are the same, regardless of the y value. So if it passes through a point with an x value of -4, all points must have an x value of -4.So the equation would be x=-4.
Line D is parallel to the line y-5 and passes through 32 Is there enough information to make a rule and equation?
yes there is it would be 10!!
Find the slope of the line that passes through these points 3 6 and 3 5?
It's not possible because the given points would be a vertical line parallel to the y axis
Is it easier to solve an equation for y first before finding points?
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
What would be an equation for the line that passes through the point -14 and is perpendicular to y equals 13x plus 4?
If -14 is the y intercept then it is: y = -1/13x -14
What is 1 fourth plus y equals x what equation would be solved in this?
That statement itself is an equation, and there are an infinite number of (x, y) pairs of numbers that satisfy it. To draw a graph of the equation, draw a straight line that rises toward the right at an angle of 45° and passes through [ y = -1/4 ] on the y-axis. The x-value and y-value of every point on that line satisfy your equation. (And we all know how many points there are on a line. Particularly on a line that has no ends.)
What equation would contain points -3 -23 and 5 9?
Points: (-3, -23) and (5, 9) Slope: 4 Equation: y = 4x-11
What would the equation of a line be if it went through the point 2 comma 2 and its yintercept was 10?
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
