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Without any equality signs the given expression can't form any equations and so therefore determining the values of x and y is not possible.

Q: Which two points satisfy y -x2 plus 2x plus 4 and x plus y 4?

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Y = 2x-5 and Y = 2x plus 7 is a linear system which intersects at points (-2,2)

That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.

If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)

y -2x when solved mathematically would remain y - 2x.

Simply substitute any value for y, solve for x for points along the line Y = 2X + 1

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There are infinitely many answers and they comprise the coordinates of all points on the line that satisfy the equation.

Y = 2x-5 and Y = 2x plus 7 is a linear system which intersects at points (-2,2)

That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.

y - 4 = 2x +1y = 2x + 5The two intercept points are (0, 5) and (-5/2, 0)

If you mean y = 2x+3 and y = -1/2x+4 then the two lines are perpendicular to each other meeting at right angles.

There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.

There are two terms which are 2x and 1

If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)

y -2x when solved mathematically would remain y - 2x.

One way would be to graph the two equations: the parabola y = xÂ² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)

2x + 2 is an algebraic expression. It is also a polynomial and it has two terms: 2x and 2.

Simply substitute any value for y, solve for x for points along the line Y = 2X + 1