x = 4 and y = 7 which will satisfy both equations
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y=2x y-2x=0 or 2x-y=0
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Solve for y.2x+y=5*subtract 2x from both sides*2x+y-2x=5-2xy=-2x+5 / y=5-2x
Yes, the point 4,8 is on the line formed by the equation y = 2x
x + 2y = 27 2x - y = 19 y = 2x - 19 x + 2(2x - 19) = 27 x + 4x - 38 = 27 5x = 65 x = 13 y = 2(13) - 19 y = 7
x = 4 and y = 7 which will satisfy both equations
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If this is related to coordinate geometry then the shading refers to the areas on the graph that satisfy the given inequations i.e if y>=2x+3 and y>= -2x+3 then the areas above both lines would be shaded.
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y=2x y-2x=0 or 2x-y=0
y=(2x)2 y=2(2x) y=4x
2x - y -(-1) = 2x - y + 1
y-2x=3 -y -y -2x=3-y -3 -3 -2x-3=-y /-1 /-1 2x+3=y y=2x and y=2x+3 have the same slope of 2, so they are parallel. Hope this helps! ;D
-2x = y^5 or y^5 = -2x y = (-2x)^(1/5)
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