There are infinitely many answers and they comprise the coordinates of all points on the line that satisfy the equation.
2x+3y=40-2x+2y=20Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.3y=-2xDivide each term in the equation by 3.(3y)/(3)=-(2x)/(3)Simplify the left-hand side of the equation by canceling the common terms.y=-(2x)/(3)if you were solving for x It would be x=-(3y)/2
x + 3y = 2 2x - 3y = 22 Add the two equations: 3x = 24 Divide both sides by 3 to give x= 8. Substitue this value of x in the first equation to give 8 + 3y = 2 Subtract 8 from both sides: 3y = -6 Divide both sides by 3: y = -2 Solution: (X, y) = (8, -2)
(A): 4x + y = 7 (B): 2x - 3y = -7 2*(B) 4x - 6y = -14 Subtract from (A) 7y = 21 Divide both sides by 7: y = 3 Substitute in (A): 4x + 3 = 7 ie 4x = 4 or x = 1 Answer: x = 1 , y = 3
-3 + 3y = 2y + 5 Add '3' to both sides Hence 3y = 2y + 8 Subtract '2y' from both sides. y = 8 The answer!!!!!
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).
2x + 3y = 1 y = 1/3 - 2x/3
(3,3)
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
2x+3y=13 3x-y=3 x=2
(-1, 0)
x=1y=2x+3y=2*1 + 3y=5
Yes and it works out that x = 3 and y = 4
- 2/3
2x + 3y + 6 = 0Subtract (2x + 6) from each side:3y = -2x - 6Divide each side by 3:y = -(2/3)x - 2Slope = -(2/3)Y-intercept = -2
It is [4m-1, (4m-2)/3]
Y=4-(2x/3)
x - 3y = -3: multiply by -2 giving -2x + 6y = 6, but -2x + 6y = 12 so we have a problem! Misprint?