Wiki User
β 6y agoWithout any equality signs the given expression can't form any equations and so therefore determining the values of x and y is not possible.
Wiki User
β 6y agoY = 2x-5 and Y = 2x plus 7 is a linear system which intersects at points (-2,2)
That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.
If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)
y -2x when solved mathematically would remain y - 2x.
Simply substitute any value for y, solve for x for points along the line Y = 2X + 1
There are infinitely many answers and they comprise the coordinates of all points on the line that satisfy the equation.
That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.
Y = 2x-5 and Y = 2x plus 7 is a linear system which intersects at points (-2,2)
y - 4 = 2x +1y = 2x + 5The two intercept points are (0, 5) and (-5/2, 0)
If you mean y = 2x+3 and y = -1/2x+4 then the two lines are perpendicular to each other meeting at right angles.
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)
There are two terms which are 2x and 1
y -2x when solved mathematically would remain y - 2x.
2x + 2 is an algebraic expression. It is also a polynomial and it has two terms: 2x and 2.
Simply substitute any value for y, solve for x for points along the line Y = 2X + 1