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How many people have the same birthday as you?
If there are 300,000,000 people in the US, then on average you share your birthday with over 82,000 people. Of course, if your birthday is 2/29, you would share it with about 1/4th of that number.
What If 2 folks share the same species what are all the levels they will share?
What If 2 folks share the same species what are all the levels they will share?
What is the probability that any two people in a random group of 30 have the same birthday that is the same month and date?
It is approaching unity that two in a random group of 30 people would have the same birthday. (Month and date)------------------------------------------------------------------------------------------------P(2 people share bd in 30) ≈ 38.0%Using the following expression* that doesn't consider February 29 of a leap year butgives good estimate;P(2 people and only 2 people share a birthday, month and date, in a group of n people) = nC2 (1/365) Π1n-1(1 - (i-1)/365)nCr = n!/(r!(n-r)!)for n = 30, r = 2,30C2 = 435P(2 people share bd in 30) = 435(1/365)(1)(1-1/365)(1-2/365)∙∙∙∙∙∙(1-27/375)(1-28/365) = 0.380215577...P(2 people share bd in 30) ≈ 38.0%*[For an expression that considers leap year see question "What is the probability thatin a room of 8 people 2 have the same birthday ?"]
Which president's birthday was on November 2nd 1865?
Warren Harding and James Polk were born on November 2. They are the only presidents who share a birthday.
How are the atoms of the elements in group 2 the same?
They share the same number of electrons (=2) in the valence shell: they have the same oxidation state of +2
What is the probability that two people selected from 30 have the same birthday?
To select the first birthday, the probability is 1/30. Having gotten that, the conditional probability that the next birthday would be the same is (1/30)x(1/29) and that is 1/870----------------------------------------------------------------------------------------------I believe the question has to be rephrased to "What is the probability that two peoplein a group of 30 people share the same birthday?". Because in the way the questionis actually stated, "the probability that two persons selected randomly from a group of 30 have the same birthday", the event that "those two people would share theirbirthday" is independent of the size of the population they were selected from.In the case the actual question be "What is the probability that two people in a groupof 30 share the same birthday?, is given by the following expression that neglectsFebruary 29 (of the leap), but gives very good approximation to the expression thatconsiders February 29 and is a simpler one. [It has to be mentioned that the analysisleading to this expression considers birthdays a "random variable" where chances fora persons birthday are the same for any day of the year]:P(2 share bd out of n) = nC2 (1/365) Π1n-1[1-(i-1)/365]for n = 30, P(2 share bd out of 30) = 30C2 (1/365) Π1 29 [1-(i-1)/365] = 435∙(1/365)∙[1-1/365]∙[1-2/365]∙[1-3/365]∙ ∙∙∙ ∙[1-28/365] = 0.380215577... ≈ 0.380 ≈ 38.0%For the construction of the expression to calculate the probability of any two people sharing a birthday in a group of n people considering Feb 29 of the leap year see thequestion "What is the probability that in a room of 8 people 2 have the same birthday?"
Which 2 countries have the same countinent?
There are many countries which share the same continent. For example: Mexico and America share the same continent, but are two seperate countries.
What 2 continent share the same land?
Europe and Asia
What is the probabililty of at least 2 people same birthday from a group of 12 people?
The probability of at least 2 people sharing a birthday in a group of 12 is approximately 0.891. This is calculated using the complement rule, finding the probability that no one shares a birthday and subtracting it from 1. The result indicates that it is highly likely for at least 2 people to share a birthday in a group of 12.
What is probability that 2 persons sharing same birth date?
The probability that two persons share the same birth date can be calculated using the concept of the birthday paradox. In a group of 23 people, there is a probability of approximately 50% that two individuals share the same birth date. This probability increases as the number of people in the group increases due to the increasing number of possible pairs to compare. The calculation involves considering the complementary probability of no one sharing a birthday and subtracting it from 1 to find the probability of at least one shared birthday.
What is the probabililty of at least 2 people same birthday from a group of 13 people?
19.4%CALCULATION:The probability of at least 2 people having the same birthday in a group of 13people is equal to one minus the probability of non of the 13 people having thesame birthday.Now, lets estimate the probability of non of the 13 people having the same birthday.(We will not consider 'leap year' for simplicity, plus it's effect on result is minimum)1. We select the 1st person. Good!.2. We select the 2nd person. The probability that he doesn't share the samebirthday with the 1st person is: 364/365.3. We select the 3rd person. The probability that he doesn't share the samebirthday with 1st and 2nd persons given that the 1st and 2nd don't share the samebirthday is: 363/365.4. And so forth until we select the 13th person. The probability that he doesn'tshare birthday with the previous 12 persons given that they also don't sharebirthdays among them is: 353/365.5. Then the probability that non of the 13 people share birthdays is:P(non of 13 share bd) = (364/365)(363/365)(362/365)∙∙∙(354/365)(353/365)P(non of 13 share bd) ≈ 0.805589724...Finally, the probability that at least 2 people share a birthday in a group of 13people is ≈ 1 - 0.80558... ≈ 0.194 ≈ 19.4%The above expression can be generalized to give the probability of at least x =2people sharing a birthday in a group of n people as:P(x≥2,n) = 1 - (1/365)n [365!/(365-n)!]
Which two faces have the same vertices faces and edges?
2 faces can't share the same face, and they cannot share ALL vertices and edges either
