Wiki User
∙ 16y agoThe probability of at least 2 people in a group of npeople sharing a common birthday can be expressed more easily (mathematically) as 1 minus the probability that nobody in the group shares a birthday. Consider two people. The probability that they don't have a common birthday is 365/365 x 364/365. So the probability that they do share a birthday is 1-(365/365 x 364/365) = 1-365x364/3652 Now consider 3 people. The probability that at least 2 share a common birthday is 1-365x364x363/3653 And so on so that the probability that at least 2 people in a group of n people having the same birthday = 1-(365x363x363x...x365-n+1)/365n = 1-365!/[ (365-n)! x 365n ]
In the case of 12 people this equates to 0.16702 (or 16.7%).
Wiki User
∙ 16y agoThe probability of at least 2 people sharing a birthday in a group of 12 is approximately 0.891. This is calculated using the complement rule, finding the probability that no one shares a birthday and subtracting it from 1. The result indicates that it is highly likely for at least 2 people to share a birthday in a group of 12.
Beryllium is the least reactive in the group 2.
Group seven is known as the halogen group. The least reactive element in group seven is astatine. Fluorine is the most reactive.
Noble gases are least reactive because they have a full shell
The group least likely to be in combination with the White group was the Black group. Historically, there have been significant social, economic, and political barriers that have separated the White and Black communities in various contexts.
It is not productive or respectful to label any member of a group as the least important. Each member contributes to the overall success and dynamic of the group.
It is 1 - 365Cn/365n. This is greater than 0.5 for n greater than or equal to 23.
10^%
19.4%CALCULATION:The probability of at least 2 people having the same birthday in a group of 13people is equal to one minus the probability of non of the 13 people having thesame birthday.Now, lets estimate the probability of non of the 13 people having the same birthday.(We will not consider 'leap year' for simplicity, plus it's effect on result is minimum)1. We select the 1st person. Good!.2. We select the 2nd person. The probability that he doesn't share the samebirthday with the 1st person is: 364/365.3. We select the 3rd person. The probability that he doesn't share the samebirthday with 1st and 2nd persons given that the 1st and 2nd don't share the samebirthday is: 363/365.4. And so forth until we select the 13th person. The probability that he doesn'tshare birthday with the previous 12 persons given that they also don't sharebirthdays among them is: 353/365.5. Then the probability that non of the 13 people share birthdays is:P(non of 13 share bd) = (364/365)(363/365)(362/365)∙∙∙(354/365)(353/365)P(non of 13 share bd) ≈ 0.805589724...Finally, the probability that at least 2 people share a birthday in a group of 13people is ≈ 1 - 0.80558... ≈ 0.194 ≈ 19.4%The above expression can be generalized to give the probability of at least x =2people sharing a birthday in a group of n people as:P(x≥2,n) = 1 - (1/365)n [365!/(365-n)!]
1-365/[(365-6)*365^6] = 1 Is this O.K ?
December 25th is considered the least popular birthday, as many people avoid scheduling births on holidays like Christmas.
On the manor, the people with the least power were the serfs.
A person shares their birthday with at least nine million different people around the world.
At least 100 all over the world.
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poor people
d.transients
my wife