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I'm still researching, but, at the moment, I would give credit to Rene Descartes who noted the relationship between the rational roots of a polynomial and the coefficients of the first and last terms. See Google Books link below (bottom of page 243 of text.
http://books.google.com/books?id=5NIDb84jOmcC&pg=PA243&lpg=PA243&dq=history+rational+roots+theorem&source=bl&ots=KYMZS2m4RE&sig=WZS7COaip1KcW4ZfLSHBgcp-Co8&hl=en&ei=3sMmStOACJqutAPFvMHFBg&sa=X&oi=book_result&ct=result&resnum=10#PPA243,M1
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Who is the founder the rational root theorem?
Rene' Descartes is credited with founding rational root theorem. He also created the rules of signs to be used with solving equations.
What is the rational root theroem?
In algebra, the rational root theorem (or rational root test, rational zero theorem or rational zero test) states a constraint on rational solutions (or roots) of a polynomialequationwith integer coefficients.If a0 and an are nonzero, then each rational solution x, when written as a fraction x = p/q in lowest terms (i.e., the greatest common divisor of p and q is 1), satisfiesp is an integer factor of the constant term a0, andq is an integer factor of the leading coefficient an.The rational root theorem is a special case (for a single linear factor) of Gauss's lemmaon the factorization of polynomials. The integral root theorem is a special case of the rational root theorem if the leading coefficient an = 1.
How do you find the two factors of one monomial and a polynomial?
1. Quadratic Formula 2. Rational Root Theorem 3. Zero Product Theorem
What is a counterexample for the rational numbers are closed under the operation of taking a square root?
2 = 2/1 is rational. Sqrt(2) is not rational.
How can you determine whether a polynomial equation has imaginary solutions?
To determine whether a polynomial equation has imaginary solutions, you must first identify what type of equation it is. If it is a quadratic equation, you can use the quadratic formula to solve for the solutions. If the equation is a cubic or higher order polynomial, you can use the Rational Root Theorem to determine if there are any imaginary solutions. The Rational Root Theorem states that if a polynomial equation has rational solutions, they must be a factor of the constant term divided by a factor of the leading coefficient. If there are no rational solutions, then the equation has imaginary solutions. To use the Rational Root Theorem, first list out all the possible rational solutions. Then, plug each possible rational solution into the equation and see if it is a solution. If there are any solutions, then the equation has imaginary solutions. If not, then there are no imaginary solutions.
Is the square root of 25 a rational number?
Oh, dude, the square root of 25 is 5, which is a whole number and can be expressed as a fraction 5/1. So, yes, it is a rational number because it can be written as a ratio of two integers. But hey, who really cares about all that math stuff anyway, right?
Is the square root of 1000 rational?
No, the square root of 1000 is not rational.
Is the sqare root of 3 rational?
No, the square root of 3 is not rational.
Is the square root of 37 rational?
is the square root of 3 rational
Is square root of 4 rational?
The square root of 4 is 2. 2 is a rational number so they square root of 4 is rational.
Is the square root of 48 rational?
The square root of 48 is a rational or irrational
Is the square root of 1500 rational?
No, the square root of 1500 is not a rational number.
