Best Answer

There are infinitely many numbers.

For example:

4, 40, 400, 4000, and so on.

or

31, 301, 310, 3001, 3010, 3100, 30001, 30010, 30100, 31000 and so on.

and then 22, 211, 13, 121, 112 and 1111 with 0s between their digits.

Q: Whose digits have a sum of 4?

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1001 1010 1100 they all are

There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.

279,999,720

18

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1001 1010 1100 they all are

There are 3 whose sum is 45 whose sum is 57 whose sum is 69 whose sum is 711 whose sum is 813 whose sum is 915 whose sum is 1017 whose sum is 1119 whose sum is 1219 whose sum is 1317 whose sum is 1415 whose sum is 1513 whose sum is 1611 whose sum is 179 whose sum is 187 whose sum is 195 whose sum is 203 whose sum is 211 whose sum is 22.

There is no pair of consecutive even integers whose sum is 264 - as their average is divisible by 4, that must mean that the sum of the unit digits of each of the pair of numbers could never be a multiple of 4 - which 264 is.

There are 5460 five digit numbers with a digit sum of 22.

There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.

279,999,720

18

I think it will be 17. The sum of digits is 8, which is the cube of 2.

56. Tens digit is greater than 4 and less than 6 so it can only be 5, so the number is 5X. It is one less than the number whose digits sum to 12, so its digits sum to 12-1 = 11 → 5 + X = 11 → X = 11 - 5 = 6 → the number is 56.