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Find a four digit number whose digits will be reversed when multiplied by nine?
The numbers are 18 and 20.
find two positive numbers whose product is a maximum. 1.) the sum is s.
To find the even two-digit numbers where the sum of the digits is 5, we need to consider the possible combinations of digits. The digits that sum up to 5 are (1,4) and (2,3). For the numbers to be even, the units digit must be 4, so the possible numbers are 14 and 34. Therefore, there are 2 even two-digit numbers where the sum of the digits is 5.
6 & 4
13 & 14 (169 & 196)
To find how many two-digit numbers have digits whose sum is a perfect square, we first note that the two-digit numbers range from 10 to 99. The possible sums of the digits (tens digit (a) and units digit (b)) can range from 1 (1+0) to 18 (9+9). The perfect squares within this range are 1, 4, 9, and 16. Analyzing each case, we find the valid combinations for each perfect square, leading to a total of 36 two-digit numbers whose digits sum to a perfect square.
Yeah, of course you can: 25, 34, 43, 52, 61, 70
Find a four digit number whose digits will be reversed when multiplied by nine?
Oh, dude, you're asking me to find prime numbers that are also into numerology? That's like asking a pineapple to do algebra. But hey, I'm up for the challenge. The prime numbers whose digits add up to 13 are 499 and 589. Just a couple of cool digits hanging out together, you know?
4 x 578 = 2312 8 x 754 = 6032
Well, 47 49 51 53 are four consecutive odd numbers those total squared has for identical digits. 40000.... The square root of any number that is only four digits long all containing the same digit has a value that is not an integer.
47
19
Write down the numbers from 1000 to 9999.
The numbers are 18 and 20.
To find numbers with distinct digits whose product is 28, we first determine the factorization of 28, which is (2^2 \times 7). The distinct digits that can be used are 1, 2, 4, 7, and 8, since they can be combined to form products equal to 28. The valid combinations of these digits are 4, 7, and 1 (as (4 \times 7 \times 1 = 28)), and 2, 4, and 7 (as (2 \times 4 \times 7 = 28)). Therefore, the valid numbers are 147, 174, 417, 471, 714, and 741 from the first combination, and 247, 274, 427, 472, 724, and 742 from the second combination, leading to a total of 12 distinct numbers.