Here is why any number to the zero power equals one.
Consider this.
a^b. it is natural to restrict a > 0, but we'll only assume that number b is any real number.
We'll use the natural exponential function defined by the derivative of the exponential function.
Now we have a^r=e^rln(a). And we know that e^rln(a)=e^((ln(a))^r), where a >0 and r is in the domain of all real numbers negative infinity to infinity.
We can apply this definition to any number a to any power r.
Particularly, a^0. By the provided definition, a^0=e^(0*ln(a))=e^0=1.
Furthermore, a^1=e^(1*ln(a))=e(ln(a))=a.
And a^2=(e^(ln(a))^2)=a^2.
Any number to the power of 0 equals 1.Therefore 2 to the power of 0 = 1
0 since anything to the power of 0 = 1
2^0=1 anything^0=1
Yes, everything to the power of 0 equals 1.
Since 2^2=4 ........1 and 2*0=0 ..........2 Dividing both sides of equation 1 by 2^2 2^2/2^2=4/2^2 => 2^(2-2)=4/4 or 2^0=1 (QED)
Any non-zero number to the power 0 equals 1.
Any value raised to the power 'zero'(0) equals '1'. Hence 2^(0) = 1 10 ^(0) = 1 Hence 2^(0) X 10^(0) = 1 x 1 = 1 the answer.
Any number raised to the power of zero equals 1. For example, start out with 2^3 = 8. Then divide by 2 and get 2^2=4. Divide by 2 again: 2^1=2. Divide by two again: 2^0=1.
0 to the power of 2 is 0, because to times 0 equals 0.
11x(2x - 1) = 0 so either 11x = 0 or x = ½
1 + 1 = 2 1 = 2 - 1 1 + 1 - 2 = 0 0 = 2 - 1 - 1
1 anything to the power of 0 is 1