0 since anything to the power of 0 = 1
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A similar question can be solved as below : If x to the power 4 plus 1 upon x to the power 4 equals 23 then what will be (x minus 1 upon x) to the power 2 equals what?a2 + b2 = (a + b)^2 - 2ab.so (x^2 )^2 + (1/x2)^2 = (x^2 + 1/x^2)^2 - 2 = 23.so (x^2 + 1/x^2) = 5.therefore(x - 1/x)^2 = (x^2 + 1/x^2) -2 = 5 -2 = 3.
2 to the 7th power equals 128....
-1 to the 7th power equals -1
logx^2=2 2logx=2 logx=1 10^1=x x=10
2 to the 8th power equals 256.