-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3
Everything to the power of 0 equals 1.
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
Anything to the zero power equals 1.
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
no false
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
21
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
-7
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
it is 121
-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
2x2 + 15 = 11x ? Can be only for some values of x.2x2 + 15 = 11x subtract 11x to both sides2x2 - 11x + 15 = 0(2x - 5)(x - 3) = 02x - 5 = 0 or x - 3 = 0x = 5/2 or x = 3
(3x-4)(x+5)