0
Binomials are used when the total of n independent trials take place and one wants to find the probability of r successes, when each success has a probability "p" of occurring. There should be independent trails, Probability of success stays the same for all trials, Fixed number of trials and Two different classifications in order to use binomial distribution.
Wiki User
∙ 9y ago
Add your answer:
Earn +20 pts
Why do you use the foil method?
To find the factor of 2 binomials
What is a method for multiplying two binomials?
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
How are patterns or methods use to solve problems involving products of two binomials?
By Trowing garbages
Is (a-3) a the sum of two terms?
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
Who invented binomials?
Carolus Linnaeus
How do you use algebra tiles to multiply two binomials?
Explain how I would use algebra times to multiply two binomials (FOIL)?
Why do you use the foil method?
To find the factor of 2 binomials
What is a method for multiplying two binomials?
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
How are patterns or methods use to solve problems involving products of two binomials?
By Trowing garbages
Does the FOIL system work for any 2 binomials?
does the FOIL system work for any binomials
What is the advantage of being able to recognize special products of binomials?
The advantage of recognizing some special binomials is that the math can then be done much more quickly. Some of the binomials appear very frequently.
How do you multiply binomials?
You use the FOIL method. First terms Outer terms Inner terms Last terms.
Is (a-3) a the sum of two terms?
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
Who discovered binomials?
Carolus Linnaeus
Who invented binomials?
Carolus Linnaeus
What cube of binomials?
(x2 + x2)=
How do you Multiply the binomials y-9 y plus 10?
To multiply two binomials you use FOIL (first, outer, inner, last): (y-9)(y+10)=y*y+10y-9y-9*10=y2+y-90
