The sun radiates in all directions, towards the earth, away from the earth, at right angles to the earth and so on. It radiates roughly equally in all these directions.
Suppose you could draw a sphere with the sun as its centre and radius = average distance between the earth and the sun (1 astronomical unit). Then the amount of incident energy is proportional to the area of cross section of the earth relative to the surface area of the sphere.
Now, mean earth-sun distance = 1 AU = 149,597,871 km
So surface area of sphere = 4*pi*r2 = 2.813*1017 km2
Radius of earth = 6371 km
Cross-sectional area of earth = 1.275*108 km2
So the earth occupies 1.275*108 /2.813*1017 of the surface area of the sphere and therefore receives 1.275*108 /2.813*1017 of the sun's energy output.
= 4.5*10-10 or approximately one half of one billionths.
Since there are no kids in space, I suggest 100%.
It is approx 7/10.
one forth by jaden
59%
It is approx 7/10: nothing at like 141234!
Of the Sun's energy reaching Earth's atmosphere, just under 60% reaches the Earth's surface. Only a small fraction of the Sun's energy reaches Earth, of course. In fact it's only about 0.000000045 percent. So, the answer to the question is: about 0.000000025 percent.
It reaches earth as an electromagnetic wave.
The energy that reaches the Earth from the sun is known as sunlight.
radiant
absorbed by earth's core
The Sun's energy is given out mainly as "electromagnetic radiation". Light is a form of electromagnetic radiation. Heat is the main form the Sun's energy has when it reaches Earth, particularly the Earth's surface.
The Sun
Nearly all of the energy that reaches Earth's surface comes from the sun.
Tornadoes come from the energy released in a thunderstorm. As powerful as they are, tornadoes account for only a tiny fraction of the energy in a thunderstorm.
half a billionth
It is done by radiation.
Solar radiation.