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128 = 8*8*2

so sqrt(128) = sqrt(8*8*2) = sqrt(8*8)*sqrt(2)

= sqrt(82)*sqrt(2)

= 8*sqrt(2) since the sqrt of a square is the number itself.

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โˆ™ 2012-06-12 19:00:39
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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: Why is the square root of 128 8 root 2?
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Related questions

What is the square root of 128?

The square root of 128 is 8 times the square root of 2 because it's an irrational number. An estimate is 11.313708498984760390413509793678


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the square root of 128 or 8 times the square root of 2.


What is the square root of negative 128 in simplest form?

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What times itself equals 128?

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What is the square root of 128 in radical form?

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The square root of 8 is 2 times the square root of 2 sqrt(8) = 2 x sqrt(2)


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To get the square root of 8, you have to multiply the root of 2 and the root of 4. The root of 4 then simplifies to 2, so the square root of 8 equals 2 times the square root of 2.


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The square root of 8 is 2 multiplied by the square root of 2


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2 is the same as the square root of 4. Square root of 4 multiplied by square root of 2 is equal to the square root of 8.


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Can someone simplify the square root of -128?

-1281/2 = -11/2 * 1281/2 = i * 1281/2 = i * 641/2 * 21/2 = i * 8 * 21/2Short of now calculating the value and writing this as a multiple of i this is as simplified as it can be.The square root of -128 = 8i * 21/2(note: x1/2 means "the square root of x").


Square root of 8 divided by square root of 2?

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What is 8 square root of 2?

There is no "8 square root" of something. You can calculate the square root, or the 8th. root, of something.


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