128 = 8*8*2
so sqrt(128) = sqrt(8*8*2) = sqrt(8*8)*sqrt(2)
= sqrt(82)*sqrt(2)
= 8*sqrt(2) since the sqrt of a square is the number itself.
The square root of 128 is 8 times the square root of 2 because it's an irrational number. An estimate is 11.313708498984760390413509793678
the square root of 128 or 8 times the square root of 2.
8√2i
128 = 64 x 2 so sqrt = 8 x root 2 or "8 root 2" 128 = 2^7 = 2^6 × 2 → √128 = √(2^6 × 2) = √(2^6) √2 = 2^3 √2 = 8 √2
8 times [ square root of 2 ] .
The square root of 128 is 8 times the square root of 2 because it's an irrational number. An estimate is 11.313708498984760390413509793678
the square root of 128 or 8 times the square root of 2.
8√2i
128 = 64 x 2 so sqrt = 8 x root 2 or "8 root 2" 128 = 2^7 = 2^6 × 2 → √128 = √(2^6 × 2) = √(2^6) √2 = 2^3 √2 = 8 √2
8 times [ square root of 2 ] .
8 x y1.5 sqrt(2)
-1281/2 = -11/2 * 1281/2 = i * 1281/2 = i * 641/2 * 21/2 = i * 8 * 21/2Short of now calculating the value and writing this as a multiple of i this is as simplified as it can be.The square root of -128 = 8i * 21/2(note: x1/2 means "the square root of x").
The square root of 8 is 2 times the square root of 2 sqrt(8) = 2 x sqrt(2)
2 is the same as the square root of 4. Square root of 4 multiplied by square root of 2 is equal to the square root of 8.
square root 2 times square root 3 times square root 8
The square root of 8 is 2 multiplied by the square root of 2
To get the square root of 8, you have to multiply the root of 2 and the root of 4. The root of 4 then simplifies to 2, so the square root of 8 equals 2 times the square root of 2.