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Q: Why is the square root of 128 8 root 2?

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The square root of 128 is 8 times the square root of 2 because it's an irrational number. An estimate is 11.313708498984760390413509793678

the square root of 128 or 8 times the square root of 2.

8√2i

8 times [ square root of 2 ] .

128 = 64 x 2 so sqrt = 8 x root 2 or "8 root 2" 128 = 2^7 = 2^6 × 2 → √128 = √(2^6 × 2) = √(2^6) √2 = 2^3 √2 = 8 √2

8 x y1.5 sqrt(2)

The square root of 8 is 2 times the square root of 2 sqrt(8) = 2 x sqrt(2)

To get the square root of 8, you have to multiply the root of 2 and the root of 4. The root of 4 then simplifies to 2, so the square root of 8 equals 2 times the square root of 2.

The square root of 8 is 2 multiplied by the square root of 2

2 is the same as the square root of 4. Square root of 4 multiplied by square root of 2 is equal to the square root of 8.

square root 2 times square root 3 times square root 8

-1281/2 = -11/2 * 1281/2 = i * 1281/2 = i * 641/2 * 21/2 = i * 8 * 21/2Short of now calculating the value and writing this as a multiple of i this is as simplified as it can be.The square root of -128 = 8i * 21/2(note: x1/2 means "the square root of x").

2

There is no "8 square root" of something. You can calculate the square root, or the 8th. root, of something.

4

It is: 2 times the square root of 2

The square root of 2 plus the square root of 2 is equal to twice the square root of 2, therefore the correct answer is: 2(√2) or √8

Sq root of 2 * sq root of 8 = 1.414 * 2.828 = 3.998792

The square root of 128, approxiametaly 11.313

The answer is: 4.24264069

It is the square root of 8

4

=SQRT(5)*SQRT(2)+SQRT(8) is 5.99070478491457

The cube root of 8 is 2

it is the square root of 16 which equals 4.