It helps to understand the integral - more specifically, the definite integral - as "adding together many pieces". If you cut up a volume into thin slices... Well, you can cut it up in many different ways, but one way this is commonly done is using parallel slices. In this case, for each of the parallel slices you basically need to figure out its area (times the thickness, expressed by "dx" or some other variable with a "d" in front) - and then you need to add all the slices up, i.e., integrate.
we can use integration.- multiple integration.
Integration can be used to calculate the area under a curve and the volume of solids of revolution.
By integration - you divide the figure into many thin slices, and calculate the volume of each slice individually. The volume of each slice, again, can be calculated by integration: divide it into thin rectangles, and calculate the area of each rectangle. If you have a irregular solid figure just immerse it in water and measure the displacement. a la Archimedes
To model the volume of a solid formed by rotating a curve around an axis using integration, you typically employ the disk or washer method. First, define the function that represents the curve and the limits of integration along the axis. Then, for the disk method, integrate the area of circular cross-sections (π times the radius squared) taken perpendicular to the axis of rotation. For the washer method, subtract the area of the inner radius from the outer radius, integrating over the same limits to find the total volume.
Geometry, or algebra (integration).
Volume of a sphere in cubic units = 4/3*pi*radius3
You could immerse it in a liquid, and measure the volume of the displaced liquid.You could also use integration techniques.You could immerse it in a liquid, and measure the volume of the displaced liquid.You could also use integration techniques.You could immerse it in a liquid, and measure the volume of the displaced liquid.You could also use integration techniques.You could immerse it in a liquid, and measure the volume of the displaced liquid.You could also use integration techniques.
To obtain the ratio of surface area to volume, divide the surface area by the volume.
Google " volume of revolution " problems and see how integration makes these problems that would not be easily solved by other methods easier.
Integration uses a summation in the definition of the definite integral, so they are not the same, but they are related. They both yield a type of sum, or area (in the case of integration).
surface area/ volume. wider range of surface area to volume is better for cells.
By integration, which basically means dividing the object into small slices and calculating the area of each slice. If the (basically 2-dimensional) slice is itself irregular, you need to apply integration once more on each slice. This topic is explored in detail in calculus courses.