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Write a java program to find the value of quadratic equation 3x-8x plus 4 for several values of x?
Wiki User
∙ 14y ago
public class QuadraticEquation { publicstatic void main(String args[]){ for(int x =0 ; x<=10; x++){ System.out.println("Value Of X : "+ x); System.out.println("------------------------"); intval = 3*x - 8*x + 4; System.out.println("Calculated Value : "+ val); System.out.println(); } } }
Wiki User
∙ 14y ago
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What is the solving for the roots of quadratic equation?
It is finding the values of the variable that make the quadratic equation true.
What are you finding when you solve a quadratic equation?
You are finding the roots or solutions. These are the values of the variable such that the quadratic equation is true. In graphical form, they are the values of the x-coordinates where the graph intersects the x-axis.
Why are x values called roots?
In math speak: Solving the equation means finding 'x' values that make the equation true. These 'x' values are called the roots of the quadratic.
How do you plot the graph of a quadratic equation?
Just like any other equation, you can set up a table of x values, and calculate the corresponding y values. Then plot the points on the graph. In this case, it helps to have some familiarity with quadratic equations (you can find a discussion in algebra books), and recognize (from the form of the equation) whether your quadratic equation represents a parabola, a circle, an ellipse, or a hyperbola.
How do you solve the quadratic equation -4y2 32y-64?
Do you mean -4y2+32y-64 = 0 otherwise it's not an equation because there's no equal sign If so then by using the quadratic equation formula the values of y both equal 4
How do you make a table of values for a quadratic equation?
Simply learn and use the quadratic equation formula.
What is the solving for the roots of quadratic equation?
It is finding the values of the variable that make the quadratic equation true.
What is the quadratic equation used for?
It is used to solve quadratic equations that cannot be factored. Usually you would factor a quadratic equation, identify the critical values and solve, but when you cannot factor you utilize the quadratic equation.
What are you finding when you solve a quadratic equation?
You are finding the roots or solutions. These are the values of the variable such that the quadratic equation is true. In graphical form, they are the values of the x-coordinates where the graph intersects the x-axis.
What are 3 other names for solutions of a quadratic equation?
Roots, zeroes, and x values are 3 other names for solutions of a quadratic equation.
How do you use the quadratic formula to solve a quadratic equation?
You convert the equation to the form: ax2 + bx + c = 0, replace the numeric values (a, b, c) in the quadratic formula, and calculate.
How do you solve for x using a quadratic equation?
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
Why are x values called roots?
In math speak: Solving the equation means finding 'x' values that make the equation true. These 'x' values are called the roots of the quadratic.
How do you plot the graph of a quadratic equation?
Just like any other equation, you can set up a table of x values, and calculate the corresponding y values. Then plot the points on the graph. In this case, it helps to have some familiarity with quadratic equations (you can find a discussion in algebra books), and recognize (from the form of the equation) whether your quadratic equation represents a parabola, a circle, an ellipse, or a hyperbola.
What is -22x equals -4xsquared plus 12?
It is a quadratic equation and the values of x are: -1/2 and 6
How do you solve the quadratic equation -4y2 32y-64?
Do you mean -4y2+32y-64 = 0 otherwise it's not an equation because there's no equal sign If so then by using the quadratic equation formula the values of y both equal 4
How do you create a function to calculate the roots of any given quadratic equation?
First rewrite the quadratic equation in the form: ax2 + bx + c = 0 where a , b and c are constant coefficients. Clearly, a is not = 0 for if it were then you would have a linear equation and not a quadratic. Then the roots of the quadratic are: x = [-b +/- sqrt(b2 - 4ac)]/2a where using the + and - values of the square root result in two solutions.
