if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
-- take two quantities that are equal to each other -- write them both on the same line, with an "equals" sign between them ( = ) You now have an equation.
x=a, where "a" equals the x-intercept (where the line crosses the x-axis)
I need step by step on my graphic calculator on how to write an equation
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
the formula for standard form is Ax+By=C
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
No, not if the y is squared. When graphed the equation will not form a straight line.
It is a straight line equation and can be rearranged into slope intercept form as follows:- 6x-6y = 12 -6y = -6x+12 y = x-2 which is now in slope intercept form
UndefinedImproved Answer:-The straight line equation is: y = 2x
find equation of the line. write equation in slope intercept form. (5,5) parallel line (3,13) and (12,13)
It is a straight line equation that can be simplified to: y = 3x-9
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
The equation of a line written in slope intercept form has the form of y = mx + b. In this form, m is the slope of the line and b is the y intercept.
"Y = any number" is perpendicular to "x = -3".
0.5 Thanks Alc :)
There are several ways to write an equation for a line. One common form is y = ax + b, where a is the slope and b is the y-intercept (where the line intercepts the y-axis).
General form for a line equation is: y=mx+b.