Q: Can you use a graph to write the equation of the line in slope-intercept form?

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y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0

Slope-Intercept form is the form y=mx+b. Sketching the graph involves plotting the line on the coordinate plane. The easiest way to do that is to create two different points from the equation, plot them on the graph and trace a line through them with a ruler. Showing your steps means showing how you got the equation. Make sure that any math you do in your head you put on the paper. Other than that I don't know how to answer this. Was there supposed to be an actual equation with it?

If you have anything that you're planning to graph, it's got to be an equation that has 'x' and 'y' in it. If you have an equation that has 'x' and 'y' in it and you're planning to graph the equation, then you've had enough elementary algebra to know how to solve the equation for 'y'. Do that first and bada bing, it'll be in slope/intercept form.

To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.

When you are trying to graph an equation.

Related questions

y = 2x + 1.

The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3

y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0

On my graphing calculator, a TI84 Plus, I can enter the equation into the Y= (a button) and then graph it by hitting the Graph button.

Slope-Intercept form is the form y=mx+b. Sketching the graph involves plotting the line on the coordinate plane. The easiest way to do that is to create two different points from the equation, plot them on the graph and trace a line through them with a ruler. Showing your steps means showing how you got the equation. Make sure that any math you do in your head you put on the paper. Other than that I don't know how to answer this. Was there supposed to be an actual equation with it?

If you have anything that you're planning to graph, it's got to be an equation that has 'x' and 'y' in it. If you have an equation that has 'x' and 'y' in it and you're planning to graph the equation, then you've had enough elementary algebra to know how to solve the equation for 'y'. Do that first and bada bing, it'll be in slope/intercept form.

A linear equation has the form of mx + b, while a quadratic equation's form is ax2+bx+c. Also, a linear equation's graph forms a line, while a quadratic equation's graph forms a parabola.

no the graph will be written in slope intercept form or y=mx+b

To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.

First write it in the "slope-intercept" form : y = mx + c Then the y-intercept is (0, c)

When you are trying to graph an equation.

Normally a quadratic equation will graph out into a parabola. The standard form is f(x)=a(x-h)2+k