(x+2)(x-4)
(2x + 4)(2x - 4) to check your answer, use the FOIL method (first, outside, inside, last) F.... 2x x 2x = 4x^2 0.... 2x x -4 = -8x I..... 2x x 4 = 8x L.... 4 x -4 = -16 so 4x^2 - 16 = (2x + 4)(2x - 4)
x+7 = 2x 2x = x+7 2x-x = 7 x = 7
f(x)= (x-7) /(-2x+7)(2x+5) set -2x+7=0 -2x=-7 x=7/2 set 2x+5=0 2x=-5 x=-5/2 x=7/2 and x=-5/2 are vertical asymptotes.
2x = 17 then x = 8.5 2x+1=7 then x = 3 2x - 1 = 7 then x = 4 which is your problem
-7 +2x = x + 8 2x - x = 7 + 8 x = 15
f(x) = 2x + 8 f(x) = -7 → 2x + 8 = -7 → 2x = -15 → x = -7½ = -7.5
It equals 7 since 2x = 7+x where 2 has 2x but 7 is one x because there is only one x . So it is 7.
2x + 52 = 7 2x + 25 = 7 2x = 7 - 25 2x = -18 x = -18/2 x = -9
4x - 7 = 2x + 5 2x - 7 = 5 2x = 12 x = 6.
2x + 7 + 2x = 23 4x + 7 = 23 4x = 16 x = 16/4 x = 4
6x-8+2x-5 = 7-2x 6x+2x+2x = 7+8+5 10x = 20 x = 20/10 x = 2