0
x^(2) + 14x = -5
x^(2) + 14x + 5 = 0
This is now in quadratic form .
It does NOT factor so use the Quadratic Eq;n.
x = { -14 +/-sqrt[(14)^2 - 4(1)(5)]} / 2(1)
x = { -14 +/- sqrt[196 - 20]} / 2 049
x = { -14 +/- sqrt[176] } / 2
x = { -14 +/- 13.266499...} / 2
x = -27.266499... / 2 = 13.633249
&
x = -0.733500838.../2 = -0.366750419...
What else can I help you with?
X2 - 14x plus 45?
x2 - 14x + 45 = (x - 9)(x - 5)
X2 plus 14x plus 45 equals 0?
x2 + 14x + 45 = 0 => x2 + 9x + 5x + 45 = 0 => x(x + 9) + 5(x + 9) = 0 (x + 9)(x + 5) = 0 so that x = -5 or x = -9
What is the derivative of F of x equals 7x squared plus 5?
14x
14x-14 equals 2x plus 46?
14x - 14 = 2x + 46 14x - 2x = 46 + 14 12x = 60 x = 5
23 equals 7x plus 7x-5?
23 = 7x + 7x - 5 = 14x - 5 14x = 23 + 5 = 28 x = 28/14 = 2
X2 - 14x plus 45?
x2 - 14x + 45 = (x - 9)(x - 5)
Factor x2 - 14x plus 45?
x2 - 14x + 45 = (x - 5)(x - 9).
X2 plus 14x plus 45 equals 0?
x2 + 14x + 45 = 0 => x2 + 9x + 5x + 45 = 0 => x(x + 9) + 5(x + 9) = 0 (x + 9)(x + 5) = 0 so that x = -5 or x = -9
What are the roots of the quadratic equation x2 - 14x plus 45 equals 0?
x2-14x+45=0(x-9)(x-5)=0x-9=0 & x-5=0x=9 & x=5
What are the roots of the quadratic equation x2 plus 14x plus 45 equals 0?
The roots are: x = -5 and x = -9
How many solutions are there to the equation 14x plus 5 equals 14x - 19?
1
What is the factorization of this polynomial -X2 - 14X - 45?
-x2-14x-45 = -(x2+14x+45) delta = 142-4*1*45=16 so x2+14x+45=(x-(-14+4)/2) (x-(-14-4)/2) = (x+5)(x+9) so -x2-14x-45 = -(x+5)(x+9)
What is the derivative of F of x equals 7x squared plus 5?
14x
14x-14 equals 2x plus 46?
14x - 14 = 2x + 46 14x - 2x = 46 + 14 12x = 60 x = 5
What number must you add to complete the square of x2 plus 14x equals -5?
Improved answer:5x2+14x+5 = 5-5x2+14x+5 = 0Solve by completing the square:(x+7)2+5 = 0(x+7)2+5-49 = 0(x+7)2 = 44x+7 = + or - the square root of 44x = -7 + or - the square root of 44
23 equals 7x plus 7x-5?
23 = 7x + 7x - 5 = 14x - 5 14x = 23 + 5 = 28 x = 28/14 = 2
X2 plus 5 equals 30?
x = +5 or -5
