x2 + 3px + p = 0
x2 + p(3x + 1) = 0
p(3x+1) = -x2
p = -x2/(3x+1)
So p can have any value at all. In fact, around x = -1/3, p goes asymptotically to + and - infinity.
no
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
-2
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
168
No.
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
-x2 + 5x - 4 = 0. Then, x2 - 5x + 4 = (x - 4)(x - 1) = 0; whence, x = 1 or 4. Checking, -1 + 5 - 4 = 0; and -16 + 20 - 4 = 0.
x = -3.27 or -6.73