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x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6

Q: X2 plus 5x plus 6 how to solve?

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x2 + 5x + 6 = (x + 2)(x + 3)

x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1

x2+5x-6 = (x+6)(x-1) when factored

x2 + 5x - 6 = x2 + 6x - x - 6 = x(x + 6) - 1(x + 6) = (x - 1)(x + 6)

=(x+3)(x+2)

Related questions

x2 + 5x + 6 = (x + 2)(x + 3)

x2 - 5x + 6 = (x - 2)(x - 3)

x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1

x2+5x+6 = (x+2)(x+3)

x2+5x-6 = (x+6)(x-1) when factored

x2 + 5x - 6 = x2 + 6x - x - 6 = x(x + 6) - 1(x + 6) = (x - 1)(x + 6)

x(x2+5x+6)

=(x+3)(x+2)

(x-6)(x+1)

x - 3

x3 + 4x2 + x - 6 = 0 x3 - x2 + 5x2 - 5x + 6x - 6 = 0 x2(x - 1) + 5x(x - 1) + 6(x - 1) = 0 (x - 1)(x2 + 5x + 6) = 0 (x - 1)(x + 2)(x + 3) = 0 So x = 1 or x = -2 or x = -3

If you mean: x2+5x+6 = 0 then the solutions are x = -3 and x = -2