If you're looking to solve that equation for x, it can be done as follows:
x2 + 9x = -7
x2 + 9x + (9/2)2 = (9/2)2 - 7
(x + 9/2)2 = 81/4 - 28/4
x + 9/2 = ±√(53/4)
x = -9/2 ± √53/2
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
The slope is 0.
4x+7=9x+7 -5x=0 x=0
-5
If: 9x+7 = 6x+25 Then: x = 6
(x+7)(x+2)
12x+14
9x + 7 = 15x + 1 ___-1_______-1 9x + 6 = 15x -9x_____-9x ____6=6x ____/6_/6 ____1=x x equals 1.
if x2 + 7 = 37, then x2 = 29 and x = ±√29
No because they don't have the same slope (9x & 3x)
9x+4 =x-7 8x=-3 x=-3/8
7x-4=9x+10-14=2xx=-7