9x+4 =x-7
8x=-3
x=-3/8
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-9x + 4 = -50 -9x = -50 - 4 -9x = -54 -x = -6 x = 6.
Subtract first from second gives -4x = 16 so x = -4 and y = -7
x = 4 9x = 7x + 8. Subtract 7x from both sides. This leaves 2x = 8. Then divide both sides by 2 to get x by itself. So, x = 4.
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
(-9x^2/√x) + 4= [-9x^2/x^(1/2)] + 4= (-9x^2)[x^(-1/2)] + 4= -9x^[2 + (-1/2)] + 4= -9x^(2 - 1/2) + 4= -9x^(3/2) + 4= -9√x^3 + 4= -9√[(x^2)(x)] + 4= -9x√x + 4Or,(-9x^2/√x) + 4= [(-9x^2)(√x)/(√x)(√x)] + 4= [(-9x^2)(√x)/√x^2] + 4= [-9(x)(x)(√x)/x] + 4 simplify x= -9x√x + 4