(x - 4)(x - 2)
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
(X + 5)(X + 1) FOIL this. X2 + 1X + 5X + 5 Gather terms. X2 + 6X + 5 ----------------------------those were the factors
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: -3 plus or minus i, where i is the square root of negative 1.
16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)
-((x + 2)(x - 8))
With great difficulty not knowing if 6x and 27 are plus or minus
Answer is x2 -6x+14 with remainder 2
x2 + 6x = x*(x + 6)
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
X2 - 6X + 27 = 0 what are the factors of 27 that add to - 6? None! This polynomial is unreal and does not intersect the X axis.
First, factorising, we get: x2 - 6x - 16 = (x - 8)(x + 2). Then, (x2 - 6x - 16) / (x - 8) = x + 2.
x2 + 6x + 8 = (x + 4)(x + 2)