the answer is 5 :D
its 5 because if y is 3 then u have to ask yourself wat times 3 + 7 is 22
44
xy^(2) - y + 2x = -3 And y = 7 Substitute for 'y' Hence x7^(2) - 7 + 2x = -3 49x + 2x - 7 = -3 51x = 4 x = 4/51 = 0.078431372....
xy = 147 x/y = 3 x = 21 y = 7
7+xy
its 5 because if y is 3 then u have to ask yourself wat times 3 + 7 is 22
44
xy^(2) - y + 2x = -3 And y = 7 Substitute for 'y' Hence x7^(2) - 7 + 2x = -3 49x + 2x - 7 = -3 51x = 4 x = 4/51 = 0.078431372....
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
*Hint*=xy=x mutiplied by y.
xy = 147 x/y = 3 x = 21 y = 7
-37
y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X
To factorize xy + 3x, we first need to factor out the common factor, which is x. This gives us x(y + 3). Therefore, the factorized form of xy + 3x is x(y + 3).
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
7+xy
6