Q: Xy 7 22 where y 3?

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its 5 because if y is 3 then u have to ask yourself wat times 3 + 7 is 22

44

xy = 147 x/y = 3 x = 21 y = 7

7+xy

6

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its 5 because if y is 3 then u have to ask yourself wat times 3 + 7 is 22

44

Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25

*Hint*=xy=x mutiplied by y.

xy = 147 x/y = 3 x = 21 y = 7

y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X

-37

Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3

7+xy

xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y

6

if you meant 2x²+y²-xy=21x=(±sqrt(-7 y^2+168)+y)/4y=(±sqrt(-7 x^2+84)+x)/2