To factorize xy + 3x, we first need to factor out the common factor, which is x. This gives us x(y + 3). Therefore, the factorized form of xy + 3x is x(y + 3).
12x2 + 7x + 1 = 12x2 + 3x + 4x + 1 = 3x*(4x + 1) + 1*(4x + 1) = (4x + 1)*(3x + 1)
The equivalent expression of 3x-9 plus 3x plus 5 is negative 4.
3x-3x+4x^2+8x=4x^2+8x
=3x+7
(x + 11)(x - 4)
X=5
x3+xy-x2y2=x(x2+y-xy2)
It is: 3(x+2)
(x + 2)(x + 1)
(x-1)(2x+5)
Factorise it: (x + 5)(3x - 8)
6x^3 + 3x = 3x(2x^2 + 1)
6y-18+xy-3x its impossible to do anything to it
6x^2 + 5x + 1 = (3x +1) (2x + 1)
12x2 - 7x + 1 = 12x2 - 4x - 3x + 1 = 4x(3x - 1) - 1(3x - 1) = (3x - 1)(4x - 1)
if you take a factor of (Y) you end up with Y(X+5Z-2).
(x + 2)(y - 3)