2x2 equals 5
2x2 + 3x - 20 = (x + 4)(2x - 5).
-11
(x-1)(2x+5)
3x-5=3x+5 There is no solution.
2x2 + 7x - 15 = 02x2 + 10x - 3x - 15 = 0(2x2 - 3x) + (10x - 15) = 0x(2x - 3) + 5(2x - 3) = 0(2x - 3)(x + 5) = 0(2x - 3) = 0 or (x + 5) = 0x = 3/2 or x = -5
what is a slope
3x+5=20 x=5 since 5x3+5=20
If: 3x-y = 5 and 2x2+y2 = 129 Then: 3x-y = 5 => y = 3x-5 And so: 2x2+(3x-5)2 = 129 => 11x2-30x-104 = 0 Using the quadratic equation formula: x = 52/11 and x = -2 By substitution points of intersection are: (52/11, 101/11) and (-2, -11)
4x + 5 = 3x + 84x-3x + 5 - 5 = 3x - 3x + 8 -5x = 3
2x2-3x-5 = (2x-5)(x+1) when factored
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then the length of the line works out as: 65/18 or 3.6111 ... recurring decimal 1