2x2-3x-5 = (2x-5)(x+1) when factored
(x + 1)(2x - 5)
8x2-3x-5 = (8x+5)(x-1) when factored
(2x - 5)(x + 1) or (2x + 5)(x - 1) depending on the sign of the term 3x
9x2 + 9x - 10 =(3x - 2)(3x + 5)
15x - 3xy = 3x(5 - y) 20 - 4y = 4(5 - y) 15x - 3xy + 20 - 4y = (3x + 4)(5 - y)
(x + 1)(2x - 5)
If you mean: 2x2+7x+5 then it is (2x+5)(x+1) when factored
(3x + 1)(x - 5)
2(x^2 - 3x - 5)
(x + 1)(2x - 5)
8x2-3x-5 = (8x+5)(x-1) when factored
(2x - 5)(x + 1) or (2x + 5)(x - 1) depending on the sign of the term 3x
9x2 + 9x - 10 =(3x - 2)(3x + 5)
The expression (x - 5) is a factor of the polynomial (2x^2 - 7x - 15) if substituting (x = 5) yields a result of zero for the polynomial. To determine this, we can use polynomial long division or synthetic division. If (2x^2 - 7x - 15) can be divided by (x - 5) without a remainder, then (x - 5) is indeed a factor of the polynomial. Otherwise, it is not a factor.
2x2 equals 5
(x + 8)(x - 5)
2x2 - 3x-5