(x + 1)(2x - 5)
8x2-3x-5 = (8x+5)(x-1) when factored
(2x - 5)(x + 1) or (2x + 5)(x - 1) depending on the sign of the term 3x
9x2 + 9x - 10 =(3x - 2)(3x + 5)
15x - 3xy = 3x(5 - y) 20 - 4y = 4(5 - y) 15x - 3xy + 20 - 4y = (3x + 4)(5 - y)
(x + 1)(2x - 5)
If you mean: 2x2+7x+5 then it is (2x+5)(x+1) when factored
(3x + 1)(x - 5)
(x + 1)(2x - 5)
2(x^2 - 3x - 5)
8x2-3x-5 = (8x+5)(x-1) when factored
(2x - 5)(x + 1) or (2x + 5)(x - 1) depending on the sign of the term 3x
9x2 + 9x - 10 =(3x - 2)(3x + 5)
2x2 equals 5
(x + 8)(x - 5)
2x2 - 3x-5
(x + 1) / (2x3 + 3x + 5) --- Can't depict long division here, but you can work this out by seeing if (x + 1) is a factor of (2x3 + 3x + 5). If it is, then the answer will be 1/(the other factor). In this case, that is true. (2x3 + 3x + 5)/(x + 1) = 2x2 - 2x + 5, so the term term above is equal to: 1 / (2x2 - 2x + 5)