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You are interested in the dimensions of a certain square A rectangle has length 5 units more than the side of this square and width half the side of this square Which equation describes this situatio?
Wiki User
∙ 12y ago
The quadratic equation of the square is probably x2-5x+6.25 = 0 because its discriminant is equal to zero giving the equation equal roots of x = 5/2 and x = 5/2
Wiki User
∙ 12y ago
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The length of a rectangle is 1 more than twice its width and the area of the rectangle is 45 what are the dimensions of the rectangle?
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
The length of a rectangle is 1 yard more than twice its width and the area of the rectangle is 66 squared Find the dimensions of the rectangle?
Let the length be 2x+1 and the width be x: (2x+1)*x = 66 square yards 2x2+x = 66 2x2+x-66 = 0 Solving the above equation by means of the quadratic equation formula will give: x = -6 or x = 5.5, so x must be the latter because dimensions can't be negative. Therefore: length = 12 yards and width = 5.5 yards Check: 12*5.5 = 66 square yards
What describes a relationship between several variables in an algebraic equation?
an algebraic equation that describes a relationship between several variables is called a?
What is the width of the rectangle if the area is 132 feet and the length is 12 feet?
The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.
You are interested in the dimensions of a certain square A rectangle has length triple the side of this square and width two units less than the side of this square Which equation describes this situ?
x^2=3x(x-2)
The base of a rectangle is 4 more than the height the area of the rectangle is 15 square inches what are the dimensions of the rectangle?
4,3Improved Answer:-The dimensions work out as: 2.358898944 and 6.358898944 inches using the quadratic equation formula
What is first length or width in this equation 22 x 44?
If that's for a rectangle, the larger of the two dimensions is usually called the "length", the other one, "width".
How do you turn this into an equation The perimeter of a rectangle is 126cm The rectangle is twice as long as it is wide What are the dimensions?
the formula for the perimeter of a rectangle is p = 2W + 2L, where L is the length and W is the width, so your first equation is 126 = 2W + 2L"twice as long as it is wide" means that the length L is 2 times the width W, so your second equation is L = 2WIn order to solve for the dimensions, you can substitute L for 2W in the first equation to get:126 = L + 2L126 = 3LL = 126/3L = 42and because L = 2W:42 = 2WW = 42/2W = 21
The length of a rectangle is 1 more than twice its width and the area of the rectangle is 45 what are the dimensions of the rectangle?
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.
What are the dimensions of a rectangle if the length is 5 feet longer than four times th width?
Anything. No area is specified, so the dimensions are w*(4w+5) This equation lacks any value to define w.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
What is the answer of equation that length multiplied by width of a rectangle?
area of the rectangle..
A rectangle is 3 times longer than it is wide The perimeter is 44 cm Find the dimensions of the rectangle?
Let x represent width. Using the formula 3x(x)=44cm, the equation is complete when x = 3.82. This means that the rectangle is 3.82 cm wide, and 11.46 cm long.
What are the dimensions of a rectangle that has an area of 600 square cm and a perimeter of 1 m showing work?
I suggest that you do the following:* Convert the meters to centimeters, to have compatible units.* Write the equation for the area of the rectangle. Replace the variable "a" (area) with the known area.* Write the equation for the perimeter of a rectangle. Replace the variable for the perimeter with the known perimeter (in cm).* Use any method to solve the simultaneous equations.Another Answer:-Let the dimensions be x and yIf: 2x+2y = 100 then x+y = 50 and x = 50-yIf: xy = 600 then (50-y)y = 600 and so 50y-y2-600 = 0Solving the quadratic equation: y = 20 or y = 30Therefore by substitution the dimensions are: when y = 20 cm then x = 30 cm
How does dimensional analysis work in real life?
Basically, if you check the dimensions of an equation and get different dimensions on the left and on the right, the equation is definitely wrong. If you get the same dimensions, it MAY be right.
What is the equation of area of a diamond?
Same as a rectangle. It is, after all, a type of rectangle (lenght >< width)
