Let the length be 2x+1 and the width be x:
(2x+1)*x = 66 square yards
2x2+x = 66
2x2+x-66 = 0
Solving the above equation by means of the quadratic equation formula will give:
x = -6 or x = 5.5, so x must be the latter because dimensions can't be negative.
Therefore: length = 12 yards and width = 5.5 yards
Check: 12*5.5 = 66 square yards
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.
The rectangle is 12 units by 3 units.
The dimensions work out as length 15 units and width 8 units Check: 2*(15+8) = 46 units which is its perimeter
Let the length be 2x and the width be x: Perimeter = 2(2x+x) = 84 4x+2x = 84 6x = 84 Divide both sides of the equation by 6 to find the value of x: x = 14 Therefore: length = 28cm and width = 14cm
The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.
if the width is 3.5 then the length is 10 10 = 3 +2(3.5) 10 x 3.5 = 35
8 ft.
The dimensions are 16 units by 8 units of mearsurement
The dimensions of the rectangle are 21 units by 9 units
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
4cm by 13cm
9" x 4"
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
It is: 15 meters by 30 meters
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.