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You lose 9.81 m/s^2 so after 4.07 seconds you will reach a maximum vertical height going 0 m/s the other 0.93 seconds will cause you to go 9.05 m/s in the downward direction. (assuming drag is negligible) In Math Terms 9.81(m/s^2) X 5 (s)= 49.05(m/s) 40(m/s)-49.05(m/s)=-9.05(m/s) 10 meters per second straight down

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Q: You throw a ball straight up with a velocity of 40 meters per second what is the balls velocity after 5 seconds?
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