3x-2y+9+9y-x = 2x+7y+9
x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5
the answer is -3x = 0
-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9
3x+5=14 3x=9 x=3
3x+2y=9 2y=9-3x y=-1.5x-4.5
3x-2y+9+9y-x = 2x+7y+9
We need to get both equations into slope-intercept form. If they are parallel, they will have the same slope. If they are perpendicular, they will have slopes that when multiplied equal -1. (unless one line is horizontal and the other vertical) 3x+2y=5 2y=5-3x y=(-3/2)x+(5/2) 3x+2y=9 2y=9-3x y=(-3/2)x+(9/2) The two lines are parallel, since both slopes are equal to (-3/2).
4x + 2y = 12 3x - 2y = 9 Have to use simultaneous equations, so add together to get : 7x = 21 so x = 3 Put it into any part of the equation 4x3 + 2y = 12 12 + 2y = 12 2y = 0 y = 0, x = 3
x + 2y = -5 2x + 3x = -9 5x = -9 x + 2y = -5 x = -2y - 5 5(-2y - 5) = -9 -10y - 25 = -9 -10y = 16 y = -5/8 x = -2y - 5 x = -2(-5/8) - 5 x = -5/4 - 5 x = -25/4 (-25/4, -5/8)
3x + y - 9 = 0
4x + 2(3x) = 30 10x = 30 x= 3. Y= 9. (3,9)
Solving for y: 5y = 9 + 2y 5y - 2y = 9 3y = 9 y = 9/3 = 3
By elimination: x = 3 and y = 0
5y = 2y+9 5y-2y = 9 3y = 9 y = 3
x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6