3x + y - 9 = 0
y = -5x
-2.25
It is the equation of a line passing through the point (0, 1/3) and with slope 4/3
1st equation: 3x+2y = 2 2nd equation: x-3y = -14 Multiply all terms in the 2nd equation by 3 and subtract it from the 1st equation:- So: 11y = 44 or y = 4 By substitution point of intersection is at: (-2, 4)
2
y = -5x
y=-x
-2.25
It is the equation of a line passing through the point (0, 1/3) and with slope 4/3
1st equation: 3x+2y = 2 2nd equation: x-3y = -14 Multiply all terms in the 2nd equation by 3 and subtract it from the 1st equation:- So: 11y = 44 or y = 4 By substitution point of intersection is at: (-2, 4)
2
y = 1/3x+4/3
Rearrange the first equation to y = 2-x and then substitute this into the second equation to form the quadratic equation: -3y2+4y-1 = 0 and when solved y = 3 or y = 1/3 Points of intersection are: (3,1) and (2 and 1/3, 1/3)
The parallel equation works out as: 4y = 3x+1 which can be expressed in the form of 3x-4y+1 = 0
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
3x-4y-6 = 0
7x-y-28 = 0